Python implementation of automatic Tic Tac Toe game using random number

Tic-tac-toe is a very popular game, so let’s implement an automatic Tic-tac-toe game using Python.

The game is automatically played by the program and hence, no user input is needed. Still, developing a automatic game will be lots of fun. Let’s see how to do this.

numpy and random Python libraries are used to build this game. Instead of asking the user to put a mark on the board, code randomly chooses a place on the board and put the mark. It will display the board after each turn unless a player wins. If the game gets draw, then it returns -1.

Explanation :
play_game() is the main function, which performs following tasks :

• Calls create_board() to create a 9×9 board and initializes with 0.
• For each player (1 or 2), calls the random_place() function to randomly choose a location on board and mark that location with the player number, alternatively.
• Print the board after each move.
• Evaluate the board after each move to check whether a row or column or a diagonal has the same player number. If so, displays the winner name. If after 9 moves, there are no winner then displays -1.

Below is the code for the above game :

# Tic-Tac-Toe Program using
# random number in Python

# importing all necessary libraries
import numpy as np
import random
from time import sleep

# Creates an empty board
def create_board():
return(np.array([[0, 0, 0],
[0, 0, 0],
[0, 0, 0]]))

# Check for empty places on board
def possibilities(board):
l = []

for i in range(len(board)):
for j in range(len(board)):

if board[i][j] == 0:
l.append((i, j))
return(l)

# Select a random place for the player
def random_place(board, player):
selection = possibilities(board)
current_loc = random.choice(selection)
board[current_loc] = player
return(board)

# Checks whether the player has three
# of their marks in a horizontal row
def row_win(board, player):
for x in range(len(board)):
win = True

for y in range(len(board)):
if board[x, y] != player:
win = False
continue

if win == True:
return(win)
return(win)

# Checks whether the player has three
# of their marks in a vertical row
def col_win(board, player):
for x in range(len(board)):
win = True

for y in range(len(board)):
if board[y][x] != player:
win = False
continue

if win == True:
return(win)
return(win)

# Checks whether the player has three
# of their marks in a diagonal row
def diag_win(board, player):
win = True
y = 0
for x in range(len(board)):
if board[x, x] != player:
win = False
win = True
if win:
for x in range(len(board)):
y = len(board) - 1 - x
if board[x, y] != player:
win = False
return win

# Evaluates whether there is
# a winner or a tie
def evaluate(board):
winner = 0

for player in [1, 2]:
if (row_win(board, player) or
col_win(board,player) or
diag_win(board,player)):

winner = player

if np.all(board != 0) and winner == 0:
winner = -1
return winner

# Main function to start the game
def play_game():
board, winner, counter = create_board(), 0, 1
print(board)
sleep(2)

while winner == 0:
for player in [1, 2]:
board = random_place(board, player)
print("Board after " + str(counter) + " move")
print(board)
sleep(2)
counter += 1
winner = evaluate(board)
if winner != 0:
break
return(winner)

# Driver Code
print("Winner is: " + str(play_game()))