Increment and Decrement operators

Increment and Decrement operators

Increment operators (++)

• Increment operators are increase the value of subsequent. value may be increase according to the programmer.
• Increment operator are two types as follows :
  1. Post increment
  2. Pre increment

 Decrement operators ( -- )

• decrement operators decrease the value to one, two and so on.
• As like Increment operators, decrement operators are also two type as :  
  
  1. Post decrement
  2. Pre decrement

Before we more discuss about increment and decrement operator, let understand some expression; that's are using in all operators.

Now some issues of pre and post increment and decrement, we will discuss after solve following programming :

 x = 5       x = 5     x = 5  
 x = x+1      ++x       x++     
 x = 6       x = 6      x=5       

In above program u notice that value of x increase to one in all three expression but after the increasing one, the final value of x in not same, third box result is differ to another two boxes. Now you know that c operators are mostly three types, ++ and -- operators are Unary operators.

Post increment or decrement are lowest precedence so it is solve at the end of program. Hence above program in third box first value of x is print i.e. 5 after, it is increase.

Unary operators are solve right to left.

Q.1 Solve the expression in C language compiler ,assuming x,z are integer variables:

z = x++ + x++

where x=7

Ans.

stepwise evaluation of this expression is shown below : 

 z = x++ + x++ + ++x

 //post increment of x=2

 z = x + x + ++x

 //++x increase the value of x one so x=8 

 /*Now all pre and post increment/decrement are  solved so we write the the expression in normal mathematical expression*/

 z = x + x + x

 //put the current value of x i.e. 8

 z = 8 + 8 + 8

 z = 24

syntax : x=current value-post increment/decrement

so x = 8 + 2

   x = 10

Q.2 Solve the following expression : 

z = ++x + y-- - ++y - x-- - x-- - ++y - x--

where   x = 7

        y = -3

Ans.

 z=++x  + y-- - ++y - x-- - x-- - ++y - x--

 /* post decrement of x=3 and

    post decrement of y=1 */

 z= ++x + y - ++y - x - x - ++y - x

 /* its unary operator so we solve it from

 right to left*/

 z=++x + y - ++y - x - x - y - x

 //now y=-3+1=-2

 z=++x + y - y - x - x - y - x

 //now y=-2+1=-1

 z=x + y - y - x - x - y - x

 //now x=7+1=8

 /*now all increment and decrement operators  

 all solved so we put the current value of x  

 and y.*/

 z= 8 + (-1) - (-1) -8 - 8 - (-1) - 8

 z= 8 - 1 + 1 - 8 - 8 + 1 - 8

 z= - 16 + 1

 z= -15

 x=8-3=5  

 y=-1-1=-2

Related some increment or decrement operators exercise:

Q.3  solve the following equations:

z = x++ + ++y - x-- + --y

where x = 7 and 
         y = 9

hint:(For your cross-checking, answer is x=7, y=9 and z=18).

Q.4 solve the following equations:

z = x++ * y++ / ++x - --y  % x++

where x = 5 and
         y = 2

hint:(For your cross-checking, answer is x=8, y=2 and z=0).

--------------------------------------------------------------------------------

Q.3 answer with explanation :

z = x++ + ++y - x-- + --y


where x = 7 and 
         y = 9

Ans:

post decrement of x = 1
post increment of x = 1

z = x + ++y - x + --y
z = x + ++y - x + y  // now y = 9-1 = 8
z = x + y - x + y      // now y = 8+1 = 9
// now put the value of x and y
z = 7 + 9 - 7 + 9
z = 9 + 9
z = 18

Hence, our final answer will be:

x = 7 - 1 + 1 = 7
y = 9
z = 18


Related program:

What will be output of below program:

int i=1;
printf("%d%d%d",i,++i,i++);